What is the answer to \sqrt[4]{3-8x^2}=2x ?

The answer to \sqrt[4]{3-8x^2}=2x is x= 1/2

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\sqrt[4]{3-8x^2}=2x

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

Take both sides of the equation to the power of

4 : 3 - 8 x^{2} = 16 x^{4}

3 - 8 x^{2} = 16 x^{4}

Solve

3 - 8 x^{2} = 16 x^{4} : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

False

The solution is

x = \frac{1}{2}

- 2 x + 4 + 2 x + 5 = 3

x^{3} = a x

x + 4 = 8 - x

90 = 9 25 v

3 x + 4 = 5

What is the answer to \sqrt[4]{3-8x^2}=2x ?
The answer to \sqrt[4]{3-8x^2}=2x is x= 1/2
Solve for x: \sqrt[4]{3-8x^2}=2x
The solution is x= 1/2