What is the answer to solvefor x,-y=\sqrt[3]{-x} ?

The answer to solvefor x,-y=\sqrt[3]{-x} is x=y^3

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solvefor x,-y=\sqrt[3]{-x}

solve for

x = y^{3}

Solution steps

Take both sides of the equation to the power of

3 : - y^{3} = - x

- y^{3} = - x

Solve

- y^{3} = - x : x = y^{3}

x = y^{3}

Verify Solutions:

x = y^{3}

True

The solution is

x = y^{3}

2 x - 1 - x - 1 = 1

5 x + 1 = 14 x + 2

x - 8 + 2 = 7

\frac{1}{2} w + 8 = - 2

y^{2} - y = 0

What is the answer to solvefor x,-y=\sqrt[3]{-x} ?
The answer to solvefor x,-y=\sqrt[3]{-x} is x=y^3