What is the answer to 2x+sqrt(x^2+x)=1 ?

The answer to 2x+sqrt(x^2+x)=1 is x=(5-sqrt(13))/6

Solve for x: 2x+sqrt(x^2+x)=1

The solution is x=(5-sqrt(13))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x + x^{2} + x = 1

x = \frac{5 - 13}{6}

Decimal Notation

x = 0.23240 \dots

Solution steps

2 x + x^{2} + x = 1

Remove square roots

x^{2} + x = 1 - 4 x + 4 x^{2}

Solve

x^{2} + x = 1 - 4 x + 4 x^{2} : x = \frac{5 + 13}{6}, x = \frac{5 - 13}{6}

x = \frac{5 + 13}{6}, x = \frac{5 - 13}{6}

Verify Solutions:

x = \frac{5 + 13}{6}

False

, x = \frac{5 - 13}{6}

True

The solution is

x = \frac{5 - 13}{6}

- 2 (x)^{3} - 4 = - 254

x + 9 = 64

x + x + 2 = 2

6 y - 2 y^{2} - 1 = 7 y - 2

4 = x + 2

What is the answer to 2x+sqrt(x^2+x)=1 ?
The answer to 2x+sqrt(x^2+x)=1 is x=(5-sqrt(13))/6
Solve for x: 2x+sqrt(x^2+x)=1
The solution is x=(5-sqrt(13))/6