What is the answer to solvefor x,f(x-3)=sqrt(x-3) ?

The answer to solvefor x,f(x-3)=sqrt(x-3) is x=(3f^2+1)/(f^2) {f 0},x=3

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solvefor x,f(x-3)=sqrt(x-3)

solve for

x, f (x - 3) = x - 3

x = \frac{3 f ^{2} + 1}{f ^{2}} {f < 0 or f > 0}, x = 3

Solution steps

f (x - 3) = x - 3

Expand

f (x - 3) : x f - 3 f

x f - 3 f = x - 3

Square both sides:

x^{2} f^{2} - 6 x f^{2} + 9 f^{2} = x - 3

x^{2} f^{2} - 6 x f^{2} + 9 f^{2} = x - 3

Solve

x^{2} f^{2} - 6 x f^{2} + 9 f^{2} = x - 3 : x = \frac{3 f ^{2} + 1}{f ^{2}}, x = 3

x = \frac{3 f ^{2} + 1}{f ^{2}}, x = 3

Verify Solutions:

x = \frac{3 f ^{2} + 1}{f ^{2}} {f < 0 or f > 0}, x = 3

True

The solutions are

x = \frac{3 f ^{2} + 1}{f ^{2}} {f < 0 or f > 0}, x = 3

x^{2} - 2 x + 1 = 2 - x

5 + 3 x = 8

6 x + 1 - 8 = 3

What is the answer to solvefor x,f(x-3)=sqrt(x-3) ?
The answer to solvefor x,f(x-3)=sqrt(x-3) is x=(3f^2+1)/(f^2) {f<0\lor f>0},x=3