What is the answer to solvefor y,x=sqrt(y-1) ?

The answer to solvefor y,x=sqrt(y-1) is y=x^2+1 {x>= 0}

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solvefor y,x=sqrt(y-1)

solve for

y, x = y - 1

y = x^{2} + 1 {x \geq 0}

Solution steps

x = y - 1

Square both sides:

x^{2} = y - 1

x^{2} = y - 1

Solve

x^{2} = y - 1 : y = x^{2} + 1

y = x^{2} + 1

Verify Solutions:

y = x^{2} + 1 {x \geq 0}

The solution is

y = x^{2} + 1 {x \geq 0}

3 x + 7 = x - 1

x - 2 = x - 8

4 - x = 0

x - 4 + x + 1 = 5

2 x + 7 - x + 7 = 1

What is the answer to solvefor y,x=sqrt(y-1) ?
The answer to solvefor y,x=sqrt(y-1) is y=x^2+1 {x>= 0}