What are the solutions to the equation x^2-2x=9 ?

The solutions to the equation x^2-2x=9 are x=1+sqrt(10),x=1-sqrt(10)

Find the zeros of x^2-2x=9

The zeros of x^2-2x=9 are x=1+sqrt(10),x=1-sqrt(10)

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x^{2} - 2 x = 9

x = 1 + 10, x = 1 - 10

Solution steps

x^{2} - 2 x = 9

Move

9

to the left side

x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 9) = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 10}{2 \cdot 1} : 1 + 10

x = \frac{- ( - 2 ) - 2 10}{2 \cdot 1} : 1 - 10

The solutions to the quadratic equation are:

x = 1 + 10, x = 1 - 10

4 x - 12 = 20

q^{2} (u - 9) + c (u - 9)

1 + 3 d \geq 10

4 (\frac{1}{4} + x) = 5

What are the solutions to the equation x^2-2x=9 ?
The solutions to the equation x^2-2x=9 are x=1+sqrt(10),x=1-sqrt(10)
Find the zeros of x^2-2x=9
The zeros of x^2-2x=9 are x=1+sqrt(10),x=1-sqrt(10)