What is the answer to solvefor y,x=sqrt(25-y^2) ?

The answer to solvefor y,x=sqrt(25-y^2) is y=sqrt(-x^2+25) {0<= x<= 5},y=-sqrt(-x^2+25) {0<= x<= 5}

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solvefor y,x=sqrt(25-y^2)

solve for

y, x = 25 - y^{2}

y = - x^{2} + 25 {0 \leq x \leq 5}, y = - - x^{2} + 25 {0 \leq x \leq 5}

Solution steps

x = 25 - y^{2}

Square both sides:

x^{2} = 25 - y^{2}

x^{2} = 25 - y^{2}

Solve

x^{2} = 25 - y^{2} : y = - x^{2} + 25, y = - - x^{2} + 25

y = - x^{2} + 25, y = - - x^{2} + 25

Verify Solutions:

y = - x^{2} + 25 {0 \leq x \leq 5}, y = - - x^{2} + 25 {0 \leq x \leq 5}

The solutions are

y = - x^{2} + 25 {0 \leq x \leq 5}, y = - - x^{2} + 25 {0 \leq x \leq 5}

20 + 0.6 x = 60 + 0.4 x - 0.006 x^{1.6}

1 + 2 + x - 5 = 2

x^{2} - x - 3 = x + 2

x - 8 - 2 x = 0

What is the answer to solvefor y,x=sqrt(25-y^2) ?
The answer to solvefor y,x=sqrt(25-y^2) is y=sqrt(-x^2+25) {0<= x<= 5},y=-sqrt(-x^2+25) {0<= x<= 5}