What is the answer to sqrt(2y+\sqrt{4y-3)}=3 ?

The answer to sqrt(2y+\sqrt{4y-3)}=3 is y=3

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sqrt(2y+\sqrt{4y-3)}=3

2 y + 4 y - 3 = 3

y = 3

Solution steps

2 y + 4 y - 3 = 3

Remove square roots

4 y - 3 = 81 - 36 y + 4 y^{2}

Solve

4 y - 3 = 81 - 36 y + 4 y^{2} : y = 7, y = 3

y = 7, y = 3

Verify Solutions:

y = 7

False

, y = 3

True

The solution is

y = 3

v - 4 = 3

3 - x = 2 x

x^{2} + 7 x + 4 - 4 x + 8 = 0

x + 1 - x = - 1

x - 4 x - 12 = 0

What is the answer to sqrt(2y+\sqrt{4y-3)}=3 ?
The answer to sqrt(2y+\sqrt{4y-3)}=3 is y=3
Solve for y: sqrt(2y+\sqrt{4y-3)}=3
The solution is y=3