What is the answer to -x+sqrt(5(x^2+2x+2))=1 ?

The answer to -x+sqrt(5(x^2+2x+2))=1 is No Solution for x\in\mathbb{R}

Solve for x: -x+sqrt(5(x^2+2x+2))=1

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x + 5 (x^{2} + 2 x + 2) = 1

No Solution for x \in R

Solution steps

- x + 5 (x^{2} + 2 x + 2) = 1

Remove square roots

5 x^{2} + 10 x + 10 = 1 + 2 x + x^{2}

Solve

5 x^{2} + 10 x + 10 = 1 + 2 x + x^{2} :

No Solution for

x \in R

No Solution for x \in R

y, x = - y^{2} - 16

x + 16 - x = 2

x - 7 = x - 5

G, 4 G - N^{2} = T

(x + 3)^{\frac{4}{3}} = 16

What is the answer to -x+sqrt(5(x^2+2x+2))=1 ?
The answer to -x+sqrt(5(x^2+2x+2))=1 is No Solution for x\in\mathbb{R}
Solve for x: -x+sqrt(5(x^2+2x+2))=1
The solution is No Solution for x\in\mathbb{R}