What is the answer to solvefor y,x=sqrt(16-y^2) ?

The answer to solvefor y,x=sqrt(16-y^2) is y=sqrt(-x^2+16) {0<= x<= 4},y=-sqrt(-x^2+16) {0<= x<= 4}

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solvefor y,x=sqrt(16-y^2)

solve for

y, x = 16 - y^{2}

y = - x^{2} + 16 {0 \leq x \leq 4}, y = - - x^{2} + 16 {0 \leq x \leq 4}

Solution steps

x = 16 - y^{2}

Square both sides:

x^{2} = 16 - y^{2}

x^{2} = 16 - y^{2}

Solve

x^{2} = 16 - y^{2} : y = - x^{2} + 16, y = - - x^{2} + 16

y = - x^{2} + 16, y = - - x^{2} + 16

Verify Solutions:

y = - x^{2} + 16 {0 \leq x \leq 4}, y = - - x^{2} + 16 {0 \leq x \leq 4}

The solutions are

y = - x^{2} + 16 {0 \leq x \leq 4}, y = - - x^{2} + 16 {0 \leq x \leq 4}

x - 2 + 5 = x + 53

y = 15

2 x = - 2 x + 5 - 1

18 - 7 x = x

What is the answer to solvefor y,x=sqrt(16-y^2) ?
The answer to solvefor y,x=sqrt(16-y^2) is y=sqrt(-x^2+16) {0<= x<= 4},y=-sqrt(-x^2+16) {0<= x<= 4}