What is the answer to solvefor y,x=y+sqrt(y) ?

The answer to solvefor y,x=y+sqrt(y) is y=(2x+1+sqrt(4x+1))/2 ,y=(2x+1-sqrt(4x+1))/2

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solvefor y,x=y+sqrt(y)

solve for

y, x = y + y

y = \frac{2 x + 1 + 4 x + 1}{2}, y = \frac{2 x + 1 - 4 x + 1}{2}

Solution steps

x = y + y

Remove square roots

x^{2} - 2 y x + y^{2} = y

Solve

x^{2} - 2 y x + y^{2} = y : y = \frac{2 x + 1 + 4 x + 1}{2}, y = \frac{2 x + 1 - 4 x + 1}{2}

y = \frac{2 x + 1 + 4 x + 1}{2}, y = \frac{2 x + 1 - 4 x + 1}{2}

Verify Solutions:

y = \frac{2 x + 1 + 4 x + 1}{2}

True

, y = \frac{2 x + 1 - 4 x + 1}{2}

True

The solutions are

y = \frac{2 x + 1 + 4 x + 1}{2}, y = \frac{2 x + 1 - 4 x + 1}{2}

2 x^{2} - 2 x + x^{2} - x = 3

2 x + 5 - x = 1

3 n = 2 n - 1

4 2 x = 2 x^{2}

500 = 3 t + 10 t + 140

What is the answer to solvefor y,x=y+sqrt(y) ?
The answer to solvefor y,x=y+sqrt(y) is y=(2x+1+sqrt(4x+1))/2 ,y=(2x+1-sqrt(4x+1))/2