What is the answer to (x-4)sqrt(3+2x-x^2)=0 ?

The answer to (x-4)sqrt(3+2x-x^2)=0 is x=-1,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-4)sqrt(3+2x-x^2)=0

(x - 4) 3 + 2 x - x^{2} = 0

x = - 1, x = 3

Solution steps

(x - 4) 3 + 2 x - x^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or 3 + 2 x - x^{2} = 0

Solve

x - 4 = 0 : x = 4

Solve

3 + 2 x - x^{2} = 0 : x = - 1, x = 3

x = 4, x = - 1, x = 3

Verify Solutions:

x = 4

False

, x = - 1

True

, x = 3

True

The solutions are

x = - 1, x = 3

2 p^{\frac{3}{2}} = 54

3 (x + 2)^{\frac{2}{3}} = 27

1 = x - 5

5 x + 1 = 4

0 = \frac{1}{2} x - 3

What is the answer to (x-4)sqrt(3+2x-x^2)=0 ?
The answer to (x-4)sqrt(3+2x-x^2)=0 is x=-1,x=3
Solve for x: (x-4)sqrt(3+2x-x^2)=0
The solution is x=-1,x=3