What is the answer to solvefor x,sqrt(x+y)=xy ?

The answer to solvefor x,sqrt(x+y)=xy is x=(1+sqrt(1+4y^3))/(2y^2),x=(1-sqrt(1+4y^3))/(2y^2)

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solvefor x,sqrt(x+y)=xy

solve for

x, x + y = x y

x = \frac{1 + 1 + 4 y ^{3}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{3}}{2 y ^{2}}

Solution steps

x + y = x y

Square both sides:

x + y = x^{2} y^{2}

x + y = x^{2} y^{2}

Solve

x + y = x^{2} y^{2} : x = \frac{1 + 1 + 4 y ^{3}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{3}}{2 y ^{2}}

x = \frac{1 + 1 + 4 y ^{3}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{3}}{2 y ^{2}}

Verify Solutions:

x = \frac{1 + 1 + 4 y ^{3}}{2 y ^{2}}

True

, x = \frac{1 - 1 + 4 y ^{3}}{2 y ^{2}}

True

The solutions are

x = \frac{1 + 1 + 4 y ^{3}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{3}}{2 y ^{2}}

x + 3 = 6

10 - x + x = - 2

x^{\frac{2}{3}} = 3

N (v) = 12 - 3 v

11 - x = x + 1

What is the answer to solvefor x,sqrt(x+y)=xy ?
The answer to solvefor x,sqrt(x+y)=xy is x=(1+sqrt(1+4y^3))/(2y^2),x=(1-sqrt(1+4y^3))/(2y^2)