What is the answer to a(x)=sqrt(x+9) ?

The answer to a(x)=sqrt(x+9) is x=(1+sqrt(1+36a^2))/(2a^2),x=(1-sqrt(1+36a^2))/(2a^2) {a 0}

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a(x)=sqrt(x+9)

a (x) = x + 9

x = \frac{1 + 1 + 36 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 36 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

Solution steps

a (x) = x + 9

Square both sides:

a^{2} x^{2} = x + 9

a^{2} x^{2} = x + 9

Solve

a^{2} x^{2} = x + 9 : x = \frac{1 + 1 + 36 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 36 a ^{2}}{2 a ^{2}}

x = \frac{1 + 1 + 36 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 36 a ^{2}}{2 a ^{2}}

Verify Solutions:

x = \frac{1 + 1 + 36 a ^{2}}{2 a ^{2}}

True

, x = \frac{1 - 1 + 36 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

The solutions are

x = \frac{1 + 1 + 36 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 36 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

2 x = 8

4 x = 8 x - 24

x - x + 29 = 1

2 + 8 x - 7 = x

What is the answer to a(x)=sqrt(x+9) ?
The answer to a(x)=sqrt(x+9) is x=(1+sqrt(1+36a^2))/(2a^2),x=(1-sqrt(1+36a^2))/(2a^2) {a<0\lor a>0}