What is the answer to sqrt(8-2x)=4-sqrt(2x+2) ?

The answer to sqrt(8-2x)=4-sqrt(2x+2) is x= 7/2 ,x=-1/2

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sqrt(8-2x)=4-sqrt(2x+2)

8 - 2 x = 4 - 2 x + 2

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

8 - 2 x = 4 - 2 x + 2

Remove square roots

16 x^{2} + 80 x + 100 = 128 x + 128

Solve

16 x^{2} + 80 x + 100 = 128 x + 128 : x = \frac{7}{2}, x = - \frac{1}{2}

x = \frac{7}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{7}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{7}{2}, x = - \frac{1}{2}

x - 4 = 0

x - 5 x + 4 = 0

x + 1 = x + 1

3 x + 7 = x + 3

x + 10 = 13 - 2 x + 3

What is the answer to sqrt(8-2x)=4-sqrt(2x+2) ?
The answer to sqrt(8-2x)=4-sqrt(2x+2) is x= 7/2 ,x=-1/2
Solve for x: sqrt(8-2x)=4-sqrt(2x+2)
The solution is x= 7/2 ,x=-1/2