What are the solutions to the equation 2x^2-24x+54=0 ?

The solutions to the equation 2x^2-24x+54=0 are x=9,x=3

Find the zeros of 2x^2-24x+54=0

The zeros of 2x^2-24x+54=0 are x=9,x=3

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2 x^{2} - 24 x + 54 = 0

x = 9, x = 3

Solution steps

2 x^{2} - 24 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 54}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 54 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 2}

x = \frac{- ( - 24 ) + 12}{2 \cdot 2} : 9

x = \frac{- ( - 24 ) - 12}{2 \cdot 2} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

(\frac{1}{3})^{0}

\frac{8 π}{9} + \frac{4 π}{3}

m^{2} - 4 m - 21

2 3^{2}

- 4 \leq \frac{g}{5}

What are the solutions to the equation 2x^2-24x+54=0 ?
The solutions to the equation 2x^2-24x+54=0 are x=9,x=3
Find the zeros of 2x^2-24x+54=0
The zeros of 2x^2-24x+54=0 are x=9,x=3