What is the answer to sqrt(z^2+6z+3)=3z+1 ?

The answer to sqrt(z^2+6z+3)=3z+1 is z= 1/2

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sqrt(z^2+6z+3)=3z+1

z^{2} + 6 z + 3 = 3 z + 1

z = \frac{1}{2}

Decimal Notation

z = 0.5

Solution steps

z^{2} + 6 z + 3 = 3 z + 1

Square both sides:

z^{2} + 6 z + 3 = 9 z^{2} + 6 z + 1

z^{2} + 6 z + 3 = 9 z^{2} + 6 z + 1

Solve

z^{2} + 6 z + 3 = 9 z^{2} + 6 z + 1 : z = \frac{1}{2}, z = - \frac{1}{2}

z = \frac{1}{2}, z = - \frac{1}{2}

Verify Solutions:

z = \frac{1}{2}

True

, z = - \frac{1}{2}

False

The solution is

z = \frac{1}{2}

5 x + 3 = 3 x

y^{\frac{3}{2}} = 5 y

3 x + 1 - x - 4 = 3

4 x = 2

What is the answer to sqrt(z^2+6z+3)=3z+1 ?
The answer to sqrt(z^2+6z+3)=3z+1 is z= 1/2
Solve for z: sqrt(z^2+6z+3)=3z+1
The solution is z= 1/2