What is the answer to solvefor x,f^{-1}(x)=sqrt(x) ?

The answer to solvefor x,f^{-1}(x)=sqrt(x) is x=f^2 {f>0},x=0 {f 0}

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solvefor x,f^{-1}(x)=sqrt(x)

solve for

x, f^{- 1} (x) = x

x = f^{2} {f > 0}, x = 0 {f < 0 or f > 0}

Solution steps

f^{- 1} (x) = x

Expand

f^{- 1} x : \frac{x}{f}

\frac{x}{f} = x

Square both sides:

\frac{x ^{2}}{f ^{2}} = x

\frac{x ^{2}}{f ^{2}} = x

Solve

\frac{x ^{2}}{f ^{2}} = x : x = f^{2}, x = 0

x = f^{2}, x = 0

Verify Solutions:

x = f^{2} {f > 0}, x = 0 {f < 0 or f > 0}

The solutions are

x = f^{2} {f > 0}, x = 0 {f < 0 or f > 0}

x^{\frac{1}{3}} = 0

2 x - 5 = 7

x^{2} - 6 x + 9 = 2

x^{\frac{1}{5}} = 7

What is the answer to solvefor x,f^{-1}(x)=sqrt(x) ?
The answer to solvefor x,f^{-1}(x)=sqrt(x) is x=f^2 {f>0},x=0 {f<0\lor f>0}