What are the solutions to the equation 10x^2-29x+10=0 ?

The solutions to the equation 10x^2-29x+10=0 are x= 5/2 ,x= 2/5

Find the zeros of 10x^2-29x+10=0

The zeros of 10x^2-29x+10=0 are x= 5/2 ,x= 2/5

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10 x^{2} - 29 x + 10 = 0

x = \frac{5}{2}, x = \frac{2}{5}

Solution steps

10 x^{2} - 29 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 29)^{2} - 4 \cdot 10 \cdot 10 = 21

x_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 10}, x_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 10}

x = \frac{- ( - 29 ) + 21}{2 \cdot 10} : \frac{5}{2}

x = \frac{- ( - 29 ) - 21}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{2}{5}

4 x^{2} + 16 x + 64

4 (x - 1) (x + 5) \leq 0

\frac{1}{2 ( 8.1 )}

\frac{3 x ^{2} y ^{2}}{9 x ^{8} y ^{8}}

16 a^{2} - 25

What are the solutions to the equation 10x^2-29x+10=0 ?
The solutions to the equation 10x^2-29x+10=0 are x= 5/2 ,x= 2/5
Find the zeros of 10x^2-29x+10=0
The zeros of 10x^2-29x+10=0 are x= 5/2 ,x= 2/5