What is the answer to \sqrt[3]{3x^2-2}=2x-1 ?

The answer to \sqrt[3]{3x^2-2}=2x-1 is x=1,x=-1/8

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\sqrt[3]{3x^2-2}=2x-1

3 3 x^{2} - 2 = 2 x - 1

x = 1, x = - \frac{1}{8}

Decimal

x = 1, x = - 0.125

Solution steps

3 3 x^{2} - 2 = 2 x - 1

Take both sides of the equation to the power of

3 : 3 x^{2} - 2 = 8 x^{3} - 12 x^{2} + 6 x - 1

3 x^{2} - 2 = 8 x^{3} - 12 x^{2} + 6 x - 1

Solve

3 x^{2} - 2 = 8 x^{3} - 12 x^{2} + 6 x - 1 : x = 1, x = - \frac{1}{8}

x = 1, x = - \frac{1}{8}

Verify Solutions:

x = 1

True

, x = - \frac{1}{8}

True

The solutions are

x = 1, x = - \frac{1}{8}

24 - 5 x - x = 0

2 = \frac{1}{c}

2 x + 22 = x + 7

4 + x^{2} = 0

4 y + 20 - y - 4 = 6

What is the answer to \sqrt[3]{3x^2-2}=2x-1 ?
The answer to \sqrt[3]{3x^2-2}=2x-1 is x=1,x=-1/8
Solve for x: \sqrt[3]{3x^2-2}=2x-1
The solution is x=1,x=-1/8