What is the answer to 2x-3x^{1/2}+1=0 ?

The answer to 2x-3x^{1/2}+1=0 is x=1,x= 1/4

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2x-3x^{1/2}+1=0

2 x - 3 x^{\frac{1}{2}} + 1 = 0

x = 1, x = \frac{1}{4}

Solution steps

2 x - 3 x^{\frac{1}{2}} + 1 = 0

Remove square roots

9 x = 4 x^{2} + 4 x + 1

Solve

9 x = 4 x^{2} + 4 x + 1 : x = 1, x = \frac{1}{4}

x = 1, x = \frac{1}{4}

Verify Solutions:

x = 1

True

, x = \frac{1}{4}

True

The solutions are

x = 1, x = \frac{1}{4}

3 - 2 x = x

8 - 7 z - z^{2} + 20 = 0

1 + 2 z = 4 z + 5 + 2 z

2 x + 9 - x = 3

2 x + 4 = x + 2

What is the answer to 2x-3x^{1/2}+1=0 ?
The answer to 2x-3x^{1/2}+1=0 is x=1,x= 1/4
Solve for x: 2x-3x^{1/2}+1=0
The solution is x=1,x= 1/4