What is the answer to sqrt(2x^2)-sqrt(3x)+1=0 ?

The answer to sqrt(2x^2)-sqrt(3x)+1=0 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(2x^2)-sqrt(3x)+1=0

The solution is No Solution for x\in\mathbb{R}

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2 x^{2} - 3 x + 1 = 0

No Solution for x \in R

Solution steps

2 x^{2} - 3 x + 1 = 0

Remove square roots

4 x^{4} - 12 x^{3} + 5 x^{2} + 6 x + 1 = 12 x

Solve

4 x^{4} - 12 x^{3} + 5 x^{2} + 6 x + 1 = 12 x : x \approx 0.18307 \dots, x \approx 2.73113 \dots

x \approx 0.18307 \dots, x \approx 2.73113 \dots

Verify Solutions:

x \approx 0.18307 \dots

False

, x \approx 2.73113 \dots

False

The solution is

No Solution for x \in R

x = x - 2

5 x + 3 = 2 x

8 = u

20 = - x^{2} + 40 x

x - 1 = x + 1

What is the answer to sqrt(2x^2)-sqrt(3x)+1=0 ?
The answer to sqrt(2x^2)-sqrt(3x)+1=0 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(2x^2)-sqrt(3x)+1=0
The solution is No Solution for x\in\mathbb{R}