What is the answer to sqrt(3x^2-2x-7)=x-1 ?

The answer to sqrt(3x^2-2x-7)=x-1 is x=2

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sqrt(3x^2-2x-7)=x-1

3 x^{2} - 2 x - 7 = x - 1

x = 2

Solution steps

3 x^{2} - 2 x - 7 = x - 1

Square both sides:

3 x^{2} - 2 x - 7 = x^{2} - 2 x + 1

3 x^{2} - 2 x - 7 = x^{2} - 2 x + 1

Solve

3 x^{2} - 2 x - 7 = x^{2} - 2 x + 1 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

False

The solution is

x = 2

x + 1 = x + 3

x + 1 = x + 4

10 + 10 m - 1 = 13

8 - x + 1 = x - 5

102 = 2 x

What is the answer to sqrt(3x^2-2x-7)=x-1 ?
The answer to sqrt(3x^2-2x-7)=x-1 is x=2
Solve for x: sqrt(3x^2-2x-7)=x-1
The solution is x=2