What is the answer to \sqrt[3]{2x^2}=2 ?

The answer to \sqrt[3]{2x^2}=2 is x=2,x=-2

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\sqrt[3]{2x^2}=2

x = 2, x = - 2

Solution steps

Take both sides of the equation to the power of

3 : 2 x^{2} = 8

2 x^{2} = 8

Solve

2 x^{2} = 8 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

4 - x = x + 2

x - 1 + 2 - x = 1

21 + 4 x = x

x - 1 = 5 - x

x - 5 = x - 3

What is the answer to \sqrt[3]{2x^2}=2 ?
The answer to \sqrt[3]{2x^2}=2 is x=2,x=-2
Solve for x: \sqrt[3]{2x^2}=2
The solution is x=2,x=-2