What is the answer to solvefor y,x=sqrt(y-3) ?

The answer to solvefor y,x=sqrt(y-3) is y=x^2+3 {x>= 0}

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solvefor y,x=sqrt(y-3)

solve for

y, x = y - 3

y = x^{2} + 3 {x \geq 0}

Solution steps

x = y - 3

Square both sides:

x^{2} = y - 3

x^{2} = y - 3

Solve

x^{2} = y - 3 : y = x^{2} + 3

y = x^{2} + 3

Verify Solutions:

y = x^{2} + 3 {x \geq 0}

The solution is

y = x^{2} + 3 {x \geq 0}

x + 6 = x + 2

x - 3 - x = - 3

0 = - x - 3 + 5

2 x = 5 + 4 - x

x - 15 x + 50 = 0

What is the answer to solvefor y,x=sqrt(y-3) ?
The answer to solvefor y,x=sqrt(y-3) is y=x^2+3 {x>= 0}