What is the answer to solvefor x,sqrt(x)-y=pi ?

The answer to solvefor x,sqrt(x)-y=pi is x=pi^2+2piy+y^2 {y>=-pi}

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solvefor x,sqrt(x)-y=pi

solve for

x, x - y = π

x = π^{2} + 2 π y + y^{2} {y \geq - π}

Solution steps

x - y = π

Move

y

to the right side

x = π + y

Square both sides:

x = π^{2} + 2 π y + y^{2}

x = π^{2} + 2 π y + y^{2}

Verify Solutions:

x = π^{2} + 2 π y + y^{2} {y \geq - π}

The solution is

x = π^{2} + 2 π y + y^{2} {y \geq - π}

(x - 10)^{\frac{3}{2}} = 64

7 x - 6 = 0

10 = 2 x - 5

x + 3 - 3 = x

3 x^{2} + 3 x = 0

What is the answer to solvefor x,sqrt(x)-y=pi ?
The answer to solvefor x,sqrt(x)-y=pi is x=pi^2+2piy+y^2 {y>=-pi}