What is the answer to solvefor y,sqrt(4y-3)=d-y ?

The answer to solvefor y,sqrt(4y-3)=d-y is y=d+2+sqrt(4d+1),y=d+2-sqrt(4d+1)

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solvefor y,sqrt(4y-3)=d-y

solve for

y, 4 y - 3 = d - y

y = d + 2 + 4 d + 1, y = d + 2 - 4 d + 1

Solution steps

4 y - 3 = d - y

Square both sides:

4 y - 3 = d^{2} - 2 y d + y^{2}

4 y - 3 = d^{2} - 2 y d + y^{2}

Solve

4 y - 3 = d^{2} - 2 y d + y^{2} : y = d + 2 + 4 d + 1, y = d + 2 - 4 d + 1

y = d + 2 + 4 d + 1, y = d + 2 - 4 d + 1

Verify Solutions:

y = d + 2 + 4 d + 1

True

, y = d + 2 - 4 d + 1

True

The solutions are

y = d + 2 + 4 d + 1, y = d + 2 - 4 d + 1

1 - x = 1 - x 4 - 7 x^{2}

5 x + 5 = 5

2 x^{\frac{4}{3}} = 162

x + 7 = 5

x - 3 = x - 1

What is the answer to solvefor y,sqrt(4y-3)=d-y ?
The answer to solvefor y,sqrt(4y-3)=d-y is y=d+2+sqrt(4d+1),y=d+2-sqrt(4d+1)