What is the answer to sqrt(3z+6)-z=2 ?

The answer to sqrt(3z+6)-z=2 is z=1,z=-2

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sqrt(3z+6)-z=2

3 z + 6 - z = 2

z = 1, z = - 2

Solution steps

3 z + 6 - z = 2

Remove square roots

3 z + 6 = 4 + 4 z + z^{2}

Solve

3 z + 6 = 4 + 4 z + z^{2} : z = 1, z = - 2

z = 1, z = - 2

Verify Solutions:

z = 1

True

, z = - 2

True

The solutions are

z = 1, z = - 2

25 - 3 x = x - 9

2 x + 7 = x + 3

x^{\frac{4}{9}} = 16

x^{2} - x - 5 = x + 2

3.7 x^{\frac{1}{2}} - 2.2 = 0