What is the answer to solvefor y,x=-sqrt(y) ?

The answer to solvefor y,x=-sqrt(y) is y=x^2 {x<= 0}

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solvefor y,x=-sqrt(y)

solve for

y, x = - y

y = x^{2} {x \leq 0}

Solution steps

x = - y

Divide both sides by

- 1

\frac{x}{- 1} = \frac{- y}{- 1}

Simplify

- x = y

Square both sides:

x^{2} = y

x^{2} = y

Switch sides

y = x^{2}

Verify Solutions:

y = x^{2} {x \leq 0}

The solution is

y = x^{2} {x \leq 0}

2 x + 9 = x + 5

5 t + 6 = - 4

x - 5 = x - 9

x^{2} + 7 - 2 x = 10

2 x + 6 - 3 = x

What is the answer to solvefor y,x=-sqrt(y) ?
The answer to solvefor y,x=-sqrt(y) is y=x^2 {x<= 0}