What is the answer to 2\sqrt[3]{x^2}-\sqrt[3]{x}=1 ?

The answer to 2\sqrt[3]{x^2}-\sqrt[3]{x}=1 is x=1,x=-1/8

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2\sqrt[3]{x^2}-\sqrt[3]{x}=1

x = 1, x = - \frac{1}{8}

Decimal Notation

x = 1, x = - 0.125

Solution steps

Use the following exponent property

Rewrite the equation with

Solve

u = 1, u = - \frac{1}{2}

Substitute back

solve for

x

Solve

x = 1, x = - \frac{1}{8}

Verify Solutions:

x = 1

True

, x = - \frac{1}{8}

True

The solutions are

x = 1, x = - \frac{1}{8}

x = 8 x

x^{- \frac{1}{2}} = \frac{2}{5}

3 x + 4 - x + 1 = 1

9 x^{\frac{2}{3}} = 4

(x - 2)^{\frac{3}{2}} = 8

What is the answer to 2\sqrt[3]{x^2}-\sqrt[3]{x}=1 ?
The answer to 2\sqrt[3]{x^2}-\sqrt[3]{x}=1 is x=1,x=-1/8
Solve for x: 2\sqrt[3]{x^2}-\sqrt[3]{x}=1
The solution is x=1,x=-1/8