What is factor (x-2)(x+2)(x+1)-4(x+2) ?

The solution to factor (x-2)(x+2)(x+1)-4(x+2) is (x+2)^2(x-3)

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factor (x-2)(x+2)(x+1)-4(x+2)

factor

(x - 2) (x + 2) (x + 1) - 4 (x + 2)

(x + 2)^{2} (x - 3)

Solution steps

(x - 2) (x + 2) (x + 1) - 4 (x + 2)

Factor out common term

x + 2

= (x + 2) ((x - 2) (x + 1) - 4)

Expand

(x - 2) (x + 1) - 4 : x^{2} - x - 6

= (x + 2) (x^{2} - x - 6)

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

= (x + 2) (x + 2) (x - 3)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x + 2)^{2} (x - 3)

\frac{1}{2} (\frac{3}{2})

\frac{11}{12} + \frac{5}{12}

1 0^{- x^{2} - 3 x} > 1 0^{- 4}

n - 8 = - 10

x^{8} y^{4}

What is factor (x-2)(x+2)(x+1)-4(x+2) ?
The solution to factor (x-2)(x+2)(x+1)-4(x+2) is (x+2)^2(x-3)