What is the answer to sqrt(x)-sqrt(2x+1)+1=0 ?

The answer to sqrt(x)-sqrt(2x+1)+1=0 is x=4,x=0

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sqrt(x)-sqrt(2x+1)+1=0

x - 2 x + 1 + 1 = 0

x = 4, x = 0

Solution steps

x - 2 x + 1 + 1 = 0

Remove square roots

x^{2} + 4 x + 4 = 8 x + 4

Solve

x^{2} + 4 x + 4 = 8 x + 4 : x = 4, x = 0

x = 4, x = 0

Verify Solutions:

x = 4

True

, x = 0

True

The solutions are

x = 4, x = 0

6 + 3 w = 2 w + 12 + 2 w

(x - 2)^{\frac{1}{3}} = 2

(x - 1)^{\frac{2}{3}} = 4

14 - 2 x = x - 7

1 + x = x^{2} + 1

What is the answer to sqrt(x)-sqrt(2x+1)+1=0 ?
The answer to sqrt(x)-sqrt(2x+1)+1=0 is x=4,x=0
Solve for x: sqrt(x)-sqrt(2x+1)+1=0
The solution is x=4,x=0