What is the answer to 2y-3=sqrt(3y^2-10y+12) ?

The answer to 2y-3=sqrt(3y^2-10y+12) is y=3

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2y-3=sqrt(3y^2-10y+12)

2 y - 3 = 3 y^{2} - 10 y + 12

y = 3

Solution steps

2 y - 3 = 3 y^{2} - 10 y + 12

Square both sides:

4 y^{2} - 12 y + 9 = 3 y^{2} - 10 y + 12

4 y^{2} - 12 y + 9 = 3 y^{2} - 10 y + 12

Solve

4 y^{2} - 12 y + 9 = 3 y^{2} - 10 y + 12 : y = 3, y = - 1

y = 3, y = - 1

Verify Solutions:

y = 3

True

, y = - 1

False

The solution is

y = 3

14 x - 6 - 3 = x

x, v = 2 a x

6 x + 64 = x - 16

x^{2} + 8 x + 6 = x^{2} + 8 x

x + 3 - 2 x + 6 = 0

What is the answer to 2y-3=sqrt(3y^2-10y+12) ?
The answer to 2y-3=sqrt(3y^2-10y+12) is y=3
Solve for y: 2y-3=sqrt(3y^2-10y+12)
The solution is y=3