What is the answer to (\sqrt[3]{x-5})-(x-5)=0 ?

The answer to (\sqrt[3]{x-5})-(x-5)=0 is x=4,x=5,x=6

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(\sqrt[3]{x-5})-(x-5)=0

x = 4, x = 5, x = 6

Solution steps

Expand

Remove roots

x - 5 = x^{3} - 15 x^{2} + 75 x - 125

Solve

x - 5 = x^{3} - 15 x^{2} + 75 x - 125 : x = 4, x = 5, x = 6

x = 4, x = 5, x = 6

Verify Solutions:

x = 4

True

, x = 5

True

, x = 6

True

The solutions are

x = 4, x = 5, x = 6

4 x^{2} - 15 = 2 x - 1

b, H = 4 b + f

x + 2 = 2 - x

What is the answer to (\sqrt[3]{x-5})-(x-5)=0 ?
The answer to (\sqrt[3]{x-5})-(x-5)=0 is x=4,x=5,x=6
Solve for x: (\sqrt[3]{x-5})-(x-5)=0
The solution is x=4,x=5,x=6