What is the answer to d=sqrt((x+2)^2+(10-3)^2) ?

The answer to d=sqrt((x+2)^2+(10-3)^2) is x=-2+sqrt(d^2-49) {d>= 7},x=-sqrt(d^2-49)-2 {d>= 7}

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d=sqrt((x+2)^2+(10-3)^2)

d = (x + 2)^{2} + (10 - 3)^{2}

x = - 2 + d^{2} - 49 {d \geq 7}, x = - d^{2} - 49 - 2 {d \geq 7}

Solution steps

d = (x + 2)^{2} + (10 - 3)^{2}

Square both sides:

d^{2} = x^{2} + 4 x + 53

d^{2} = x^{2} + 4 x + 53

Solve

d^{2} = x^{2} + 4 x + 53 : x = - 2 + d^{2} - 49, x = - d^{2} - 49 - 2

x = - 2 + d^{2} - 49, x = - d^{2} - 49 - 2

Verify Solutions:

x = - 2 + d^{2} - 49 {d \geq 7}, x = - d^{2} - 49 - 2 {d \geq 7}

The solutions are

x = - 2 + d^{2} - 49 {d \geq 7}, x = - d^{2} - 49 - 2 {d \geq 7}

4 x^{2} - x^{2} = 6

(x - 5)^{\frac{2}{3}} = 49

(x - 5)^{\frac{2}{3}} = 64

(x - 5)^{\frac{2}{3}} = 36

What is the answer to d=sqrt((x+2)^2+(10-3)^2) ?
The answer to d=sqrt((x+2)^2+(10-3)^2) is x=-2+sqrt(d^2-49) {d>= 7},x=-sqrt(d^2-49)-2 {d>= 7}