What is the answer to sqrt(2x+1)^2=sqrt(x)^2 ?

The answer to sqrt(2x+1)^2=sqrt(x)^2 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(2x+1)^2=sqrt(x)^2

The solution is No Solution for x\in\mathbb{R}

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2 x + 1^{2} = x^{2}

No Solution for x \in R

Solution steps

(2 x + 1)^{2} = (x)^{2}

Move

(x)^{2}

to the left side

(2 x + 1)^{2} - (x)^{2} = 0

Factor

(2 x + 1)^{2} - (x)^{2} : (2 x + 1 + x) (2 x + 1 - x)

(2 x + 1 + x) (2 x + 1 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 + x = 0 or 2 x + 1 - x = 0

Solve

2 x + 1 + x = 0 :

No Solution for

x \in R

Solve

2 x + 1 - x = 0 :

No Solution for

x \in R

No Solution for x \in R

A, U = n A - r

x + 8 - 5 = 0

1 - p = - 8 - 2 p

4 x + 9 + 3 = x

What is the answer to sqrt(2x+1)^2=sqrt(x)^2 ?
The answer to sqrt(2x+1)^2=sqrt(x)^2 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(2x+1)^2=sqrt(x)^2
The solution is No Solution for x\in\mathbb{R}