What is the answer to solvefor x,sqrt(x)+y=0 ?

The answer to solvefor x,sqrt(x)+y=0 is x=y^2 {y<= 0}

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solvefor x,sqrt(x)+y=0

solve for

x, x + y = 0

x = y^{2} {y \leq 0}

Solution steps

x + y = 0

Move

y

to the right side

x = - y

Square both sides:

x = y^{2}

x = y^{2}

Verify Solutions:

x = y^{2} {y \leq 0}

The solution is

x = y^{2} {y \leq 0}

2 x + 9 - x + 1 = 2

3 t + 5 = 7

2 x + 3 = 4 x - 2

7 x + 2 + x = 6

5 x + 4 = 3

What is the answer to solvefor x,sqrt(x)+y=0 ?
The answer to solvefor x,sqrt(x)+y=0 is x=y^2 {y<= 0}