What are the solutions to the equation 36-4.9(x)^2=10 ?

The solutions to the equation 36-4.9(x)^2=10 are x=(2sqrt(65))/7 ,x=-(2sqrt(65))/7

Find the zeros of 36-4.9(x)^2=10

The zeros of 36-4.9(x)^2=10 are x=(2sqrt(65))/7 ,x=-(2sqrt(65))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

36 - 4.9 (x)^{2} = 10

x = \frac{2 65}{7}, x = - \frac{2 65}{7}

Decimal Notation

x = 2.30350 \dots, x = - 2.30350 \dots

Solution steps

36 - 4.9 x^{2} = 10

Move

36

to the right side

- 4.9 x^{2} = - 26

Multiply both sides by

10

- 49 x^{2} = - 260

Divide both sides by

- 49

x^{2} = \frac{260}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{260}{49}, x = - \frac{260}{49}

\frac{260}{49} = \frac{2 65}{7}

- \frac{260}{49} = - \frac{2 65}{7}

x = \frac{2 65}{7}, x = - \frac{2 65}{7}

(\frac{2}{7})^{2}

- 6 \leq \frac{2 x + 11}{7} < 2

(\frac{x ^{2}}{y ^{3}})^{5}

(x + 2) (x - 2)

81 x^{4} - y^{4}

What are the solutions to the equation 36-4.9(x)^2=10 ?
The solutions to the equation 36-4.9(x)^2=10 are x=(2sqrt(65))/7 ,x=-(2sqrt(65))/7
Find the zeros of 36-4.9(x)^2=10
The zeros of 36-4.9(x)^2=10 are x=(2sqrt(65))/7 ,x=-(2sqrt(65))/7