What is the answer to solvefor x,sqrt(2x+y-3z)=5 ?

The answer to solvefor x,sqrt(2x+y-3z)=5 is x=(25-y+3z)/2

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solvefor x,sqrt(2x+y-3z)=5

solve for

x, 2 x + y - 3 z = 5

x = \frac{25 - y + 3 z}{2}

Solution steps

2 x + y - 3 z = 5

Square both sides:

2 x + y - 3 z = 25

2 x + y - 3 z = 25

Solve

2 x + y - 3 z = 25 : x = \frac{25 - y + 3 z}{2}

x = \frac{25 - y + 3 z}{2}

x - 5 = 2 x - 5

(x - 4)^{\frac{5}{2}} = 32

y, x = - 2 y - y^{2}

N, ma - N = r

What is the answer to solvefor x,sqrt(2x+y-3z)=5 ?
The answer to solvefor x,sqrt(2x+y-3z)=5 is x=(25-y+3z)/2