What is the answer to solvefor y,x=sqrt(9-y^2) ?

The answer to solvefor y,x=sqrt(9-y^2) is y=sqrt(-x^2+9) {0<= x<= 3},y=-sqrt(-x^2+9) {0<= x<= 3}

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solvefor y,x=sqrt(9-y^2)

solve for

y, x = 9 - y^{2}

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

Solution steps

x = 9 - y^{2}

Square both sides:

x^{2} = 9 - y^{2}

x^{2} = 9 - y^{2}

Solve

x^{2} = 9 - y^{2} : y = - x^{2} + 9, y = - - x^{2} + 9

y = - x^{2} + 9, y = - - x^{2} + 9

Verify Solutions:

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

The solutions are

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

x + 2 - 1 = - 2 - 2 x

x^{2} - 6 x = 4

- 18 x^{\frac{1}{2}} = x + 81

What is the answer to solvefor y,x=sqrt(9-y^2) ?
The answer to solvefor y,x=sqrt(9-y^2) is y=sqrt(-x^2+9) {0<= x<= 3},y=-sqrt(-x^2+9) {0<= x<= 3}