What is the answer to 2sqrt(y+2)=(2(y+2))/3 ?

The answer to 2sqrt(y+2)=(2(y+2))/3 is y=7,y=-2

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2sqrt(y+2)=(2(y+2))/3

2 y + 2 = \frac{2 ( y + 2 )}{3}

y = 7, y = - 2

Solution steps

2 y + 2 = \frac{2 ( y + 2 )}{3}

Multiply both sides by

3

2 y + 2 \cdot 3 = \frac{2 ( y + 2 )}{3} \cdot 3

Simplify

6 y + 2 = 2 (y + 2)

Expand

2 (y + 2) : 2 y + 4

6 y + 2 = 2 y + 4

Square both sides:

36 y + 72 = 4 y^{2} + 16 y + 16

36 y + 72 = 4 y^{2} + 16 y + 16

Solve

36 y + 72 = 4 y^{2} + 16 y + 16 : y = 7, y = - 2

y = 7, y = - 2

Verify Solutions:

y = 7

True

, y = - 2

True

The solutions are

y = 7, y = - 2

3 x + 10 + 1 = 6 - 3 x + 3

x^{2} - 63 = 1

x - 2 x + 2 = 0

x + 4 - x - 1 = 1

2 - x = 42.5

What is the answer to 2sqrt(y+2)=(2(y+2))/3 ?
The answer to 2sqrt(y+2)=(2(y+2))/3 is y=7,y=-2
Solve for y: 2sqrt(y+2)=(2(y+2))/3
The solution is y=7,y=-2