What is the answer to solvefor x,y-sqrt(x-1)=2 ?

The answer to solvefor x,y-sqrt(x-1)=2 is x=y^2-4y+5 {y>= 2}

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solvefor x,y-sqrt(x-1)=2

solve for

x, y - x - 1 = 2

x = y^{2} - 4 y + 5 {y \geq 2}

Solution steps

y - x - 1 = 2

Move

y

to the right side

- x - 1 = 2 - y

Square both sides:

x - 1 = 4 - 4 y + y^{2}

x - 1 = 4 - 4 y + y^{2}

Solve

x - 1 = 4 - 4 y + y^{2} : x = y^{2} - 4 y + 5

x = y^{2} - 4 y + 5

Verify Solutions:

x = y^{2} - 4 y + 5 {y \geq 2}

The solution is

x = y^{2} - 4 y + 5 {y \geq 2}

81 - z - z = 9

8 x + 5 = 14 x

y, x = 2 y

- 3 x + 1 + 2 x - 1 = 0

x^{\frac{3}{7}} = 8

What is the answer to solvefor x,y-sqrt(x-1)=2 ?
The answer to solvefor x,y-sqrt(x-1)=2 is x=y^2-4y+5 {y>= 2}