What is the answer to solvefor a,a^{-1/2}=x ?

The answer to solvefor a,a^{-1/2}=x is a= 1/(x^2) {x 0}

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solvefor a,a^{-1/2}=x

solve for

a, a^{- \frac{1}{2}} = x

a = \frac{1}{x ^{2}} {x < 0 or x > 0}

Solution steps

a^{- \frac{1}{2}} = x

Take both sides of the equation to the power of

- 2 : a = \frac{1}{x ^{2}}

a = \frac{1}{x ^{2}}

Verify Solutions:

a = \frac{1}{x ^{2}} {x < 0 or x > 0}

The solution is

a = \frac{1}{x ^{2}} {x < 0 or x > 0}

x, 3 x - 2 - 8 = 8

\frac{27}{x x} = x x

x^{2} = 5

x^{2} = 0

16 - 6 x = x

What is the answer to solvefor a,a^{-1/2}=x ?
The answer to solvefor a,a^{-1/2}=x is a= 1/(x^2) {x<0\lor x>0}