What is the answer to solvefor y,x=sqrt(y-2) ?

The answer to solvefor y,x=sqrt(y-2) is y=x^2+2 {x>= 0}

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solvefor y,x=sqrt(y-2)

solve for

y, x = y - 2

y = x^{2} + 2 {x \geq 0}

Solution steps

x = y - 2

Square both sides:

x^{2} = y - 2

x^{2} = y - 2

Solve

x^{2} = y - 2 : y = x^{2} + 2

y = x^{2} + 2

Verify Solutions:

y = x^{2} + 2 {x \geq 0}

The solution is

y = x^{2} + 2 {x \geq 0}

2 x + x + 7 = 7

5 x - 9 = 0

0.2 x^{0.7} = 0.2 x^{0.1}

x + 6 = x + 6

What is the answer to solvefor y,x=sqrt(y-2) ?
The answer to solvefor y,x=sqrt(y-2) is y=x^2+2 {x>= 0}