What is the answer to -3x(2-x^2)^{1/2}=0 ?

The answer to -3x(2-x^2)^{1/2}=0 is x=0,x=sqrt(2),x=-sqrt(2)

Solve for x: -3x(2-x^2)^{1/2}=0

The solution is x=0,x=sqrt(2),x=-sqrt(2)

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- 3 x (2 - x^{2})^{\frac{1}{2}} = 0

x = 0, x = 2, x = - 2

Decimal Notation

x = 0, x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

- 3 x (2 - x^{2})^{\frac{1}{2}} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or (2 - x^{2})^{\frac{1}{2}} = 0

Solve

(2 - x^{2})^{\frac{1}{2}} = 0 : x = 2, x = - 2

x = 0, x = 2, x = - 2

Verify Solutions:

x = 0

True

, x = 2

True

, x = - 2

True

The solutions are

x = 0, x = 2, x = - 2

(2 x + 1)^{\frac{1}{3}} = - 3

12 x - 32 = x

x = 2 + x

What is the answer to -3x(2-x^2)^{1/2}=0 ?
The answer to -3x(2-x^2)^{1/2}=0 is x=0,x=sqrt(2),x=-sqrt(2)
Solve for x: -3x(2-x^2)^{1/2}=0
The solution is x=0,x=sqrt(2),x=-sqrt(2)