What is the answer to sqrt((k-1)^2+(2+1)^2)=5 ?

The answer to sqrt((k-1)^2+(2+1)^2)=5 is k=5,k=-3

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sqrt((k-1)^2+(2+1)^2)=5

(k - 1)^{2} + (2 + 1)^{2} = 5

k = 5, k = - 3

Solution steps

(k - 1)^{2} + (2 + 1)^{2} = 5

Square both sides:

k^{2} - 2 k + 10 = 25

k^{2} - 2 k + 10 = 25

Solve

k^{2} - 2 k + 10 = 25 : k = 5, k = - 3

k = 5, k = - 3

Verify Solutions:

k = 5

True

, k = - 3

True

The solutions are

k = 5, k = - 3

5 x - 4 = 6

8 x + 1 - 5 = 0

\frac{x ^{2} - x - 1}{x - 1} = 1

x^{2} + 1 = x + 1

x = 2 x 16 - x^{2}

What is the answer to sqrt((k-1)^2+(2+1)^2)=5 ?
The answer to sqrt((k-1)^2+(2+1)^2)=5 is k=5,k=-3
Solve for k: sqrt((k-1)^2+(2+1)^2)=5
The solution is k=5,k=-3