What is the answer to (x^2-4)sqrt(1-7x)=0 ?

The answer to (x^2-4)sqrt(1-7x)=0 is x= 1/7 ,x=-2

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(x^2-4)sqrt(1-7x)=0

(x^{2} - 4) 1 - 7 x = 0

x = \frac{1}{7}, x = - 2

Decimal Notation

x = 0.14285 \dots, x = - 2

Solution steps

(x^{2} - 4) 1 - 7 x = 0

Factor

(x^{2} - 4) 1 - 7 x : 1 - 7 x (x + 2) (x - 2)

1 - 7 x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 - 7 x = 0 or x + 2 = 0 or x - 2 = 0

Solve

1 - 7 x = 0 : x = \frac{1}{7}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

x = \frac{1}{7}, x = - 2, x = 2

Verify Solutions:

x = \frac{1}{7}

True

, x = - 2

True

, x = 2

False

The solutions are

x = \frac{1}{7}, x = - 2

4 x + 4 = 28

y^{\frac{3}{2}} = 6 y

2 x + x + 1 = 0

3 (x + 1)^{\frac{4}{3}} = 48

What is the answer to (x^2-4)sqrt(1-7x)=0 ?
The answer to (x^2-4)sqrt(1-7x)=0 is x= 1/7 ,x=-2
Solve for x: (x^2-4)sqrt(1-7x)=0
The solution is x= 1/7 ,x=-2