What is the answer to solvefor y,x=-sqrt(y+1) ?

The answer to solvefor y,x=-sqrt(y+1) is y=x^2-1 {x<= 0}

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solvefor y,x=-sqrt(y+1)

solve for

y, x = - y + 1

y = x^{2} - 1 {x \leq 0}

Solution steps

x = - y + 1

Divide both sides by

- 1

\frac{x}{- 1} = \frac{- y + 1}{- 1}

Simplify

- x = y + 1

Square both sides:

x^{2} = y + 1

x^{2} = y + 1

Solve

x^{2} = y + 1 : y = x^{2} - 1

y = x^{2} - 1

Verify Solutions:

y = x^{2} - 1 {x \leq 0}

The solution is

y = x^{2} - 1 {x \leq 0}

x - 1 = x - 1

x^{\frac{1}{3}} = 6

x + 5 + 7 = 10

2 x + 5 = x + 1

What is the answer to solvefor y,x=-sqrt(y+1) ?
The answer to solvefor y,x=-sqrt(y+1) is y=x^2-1 {x<= 0}