What are the solutions to the equation 4^2+x^2=9^2 ?

The solutions to the equation 4^2+x^2=9^2 are x=sqrt(65),x=-sqrt(65)

Find the zeros of 4^2+x^2=9^2

The zeros of 4^2+x^2=9^2 are x=sqrt(65),x=-sqrt(65)

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4^{2} + x^{2} = 9^{2}

x = 65, x = - 65

Decimal Notation

x = 8.06225 \dots, x = - 8.06225 \dots

Solution steps

4^{2} + x^{2} = 9^{2}

Move

4^{2}

to the right side

x^{2} = 65

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 65, x = - 65

x - 16 = 9

\frac{x}{3} + \frac{4 x}{5} = \frac{1}{3}

15 - 2 x = - 1

\frac{10}{3} = \frac{x}{( - \frac{5}{2} )}

- 4 x + 3 (x - 1) = - 2

What are the solutions to the equation 4^2+x^2=9^2 ?
The solutions to the equation 4^2+x^2=9^2 are x=sqrt(65),x=-sqrt(65)
Find the zeros of 4^2+x^2=9^2
The zeros of 4^2+x^2=9^2 are x=sqrt(65),x=-sqrt(65)