What is the answer to sqrt(x^2-x-6)=sqrt(x-3) ?

The answer to sqrt(x^2-x-6)=sqrt(x-3) is x=3

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sqrt(x^2-x-6)=sqrt(x-3)

x^{2} - x - 6 = x - 3

x = 3

Solution steps

x^{2} - x - 6 = x - 3

Square both sides:

x^{2} - x - 6 = x - 3

x^{2} - x - 6 = x - 3

Solve

x^{2} - x - 6 = x - 3 : x = 3, x = - 1

x = 3, x = - 1

Verify Solutions:

x = 3

True

, x = - 1

False

The solution is

x = 3

x + 4 - 7 = 0

A, B A - h = t

\frac{1}{2} x - 3 = 0

2 x + 1 + x = 7

2 x + 1 = 3 x - 1

What is the answer to sqrt(x^2-x-6)=sqrt(x-3) ?
The answer to sqrt(x^2-x-6)=sqrt(x-3) is x=3
Solve for x: sqrt(x^2-x-6)=sqrt(x-3)
The solution is x=3